如何从一个php文件向另一个地址post数据，不用表单和隐藏的变量

可以使用以下函数来实现：

<?php
function posttohost($url, $data) {
$url = parse_url($url);
if (!$url) return "couldn"t parse url";
if (!isset($url["port"])) { $url["port"] = ""; }
if (!isset($url["query"])) { $url["query"] = ""; }

$encoded = "";

while (list($k,$v) = each($data)) {
$encoded .= ($encoded ? "&" : "");
$encoded .= rawurlencode($k)."=".rawurlencode($v);
}

$fp = fsockopen($url["host"], $url["port"] ? $url["port"] : 80);
if (!$fp) return "Failed to open socket to $url[host]"; 数据挖掘研究院

fputs($fp, sprintf("POST %s%s%s HTTP/1.0 ", $url["path"], $url["query"] ? "?" : "", $url["query"]));
fputs($fp, "Host: $url[host] ");
fputs($fp, "Content-type: application/x-www-form-urlencoded ");
fputs($fp, "Content-length: " . strlen($encoded) . " ");
fputs($fp, "Connection: close "); 数据挖掘研究院

fputs($fp, "$encoded "); 数据挖掘研究院

$line = fgets($fp,1024);
if (!eregi("^HTTP/1.. 200", $line)) return; 数据挖掘研究院

$results = ""; $inheader = 1;
while(!feof($fp)) {
$line = fgets($fp,1024);
if ($inheader && ($line == " " || $line == " ")) {
$inheader = 0;
}
elseif (!$inheader) {
$results .= $line;
}
}
fclose($fp);

数据挖掘研究院

return $results;
}
?>
--------------------------------------------------------------------------------------------------
也可以这样 数据挖掘研究院

<?php
$URL="www.mysite.com/test.php";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"https://$URL");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "Data1=blah&Data2=blah");
curl_exec ($ch);
curl_close ($ch);
?> 数据挖掘研究院